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Simplifying x2 + 1.25x + -159 = 0 Reorder the terms: -159 + 1.25x + x2 = 0 Solving -159 + 1.25x + x2 = 0 Solving for variable 'x'. Begin completing the square. Move the constant term to the right: Add '159' to each side of the equation. -159 + 1.25x + 159 + x2 = 0 + 159 Reorder the terms: -159 + 159 + 1.25x + x2 = 0 + 159 Combine like terms: -159 + 159 = 0 0 + 1.25x + x2 = 0 + 159 1.25x + x2 = 0 + 159 Combine like terms: 0 + 159 = 159 1.25x + x2 = 159 The x term is 1.25x. Take half its coefficient (0.625). Square it (0.390625) and add it to both sides. Add '0.390625' to each side of the equation. 1.25x + 0.390625 + x2 = 159 + 0.390625 Reorder the terms: 0.390625 + 1.25x + x2 = 159 + 0.390625 Combine like terms: 159 + 0.390625 = 159.390625 0.390625 + 1.25x + x2 = 159.390625 Factor a perfect square on the left side: (x + 0.625)(x + 0.625) = 159.390625 Calculate the square root of the right side: 12.625 Break this problem into two subproblems by setting (x + 0.625) equal to 12.625 and -12.625.Subproblem 1
x + 0.625 = 12.625 Simplifying x + 0.625 = 12.625 Reorder the terms: 0.625 + x = 12.625 Solving 0.625 + x = 12.625 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-0.625' to each side of the equation. 0.625 + -0.625 + x = 12.625 + -0.625 Combine like terms: 0.625 + -0.625 = 0.000 0.000 + x = 12.625 + -0.625 x = 12.625 + -0.625 Combine like terms: 12.625 + -0.625 = 12 x = 12 Simplifying x = 12Subproblem 2
x + 0.625 = -12.625 Simplifying x + 0.625 = -12.625 Reorder the terms: 0.625 + x = -12.625 Solving 0.625 + x = -12.625 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-0.625' to each side of the equation. 0.625 + -0.625 + x = -12.625 + -0.625 Combine like terms: 0.625 + -0.625 = 0.000 0.000 + x = -12.625 + -0.625 x = -12.625 + -0.625 Combine like terms: -12.625 + -0.625 = -13.25 x = -13.25 Simplifying x = -13.25Solution
The solution to the problem is based on the solutions from the subproblems. x = {12, -13.25}
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